Latest must have in laptop power

[Painless]

My better half just sugested I add this to my tool box :) !!



http://painless-computing.co.uk/latest%20must%20have.jpg

John

[TLE]

That would have been a good one for April the 1st.

[Knightsman]

HAHAHA, Awesome





.................

[kevinjhaag]

Ha Ha Ha... If only that was true. Then electric cars would run many many miles too.

[bytes]

Hold up!!!.......... that's not real? :D

[Tristan]

I just bought a pallet of these to resell in my store. :rolleyes:

[Martyn]

Do they do a longer version for laptops with the usbs and power on opposite sides? :rolleyes:

[TLE]

Do they do a longer version for laptops with the usbs and power on opposite sides? :rolleyes:

You could sell them and extension lead as well Martyn.

[PC Ops]

I'm pretty sure I can get someone to 'try this out' Lol!

[JosephLeo]

My common sense is tingling.

How can this possibly work on USB? USB 3.0 (the newest iteration of the technology) can support up to 900 mA on one port. A typical laptop battery will need like what- 3,000 to 4,000 mA? You're going to need to at least use a 3 way usb splitter on this. And that's only if you have USB 3.0. You're going to need a lot of USB 2.0 ports, and you're pretty much in the dark (pun not intended) with USB 1.0.

However, given the size of the cable. I want to guess that this is the netbook model. 900mA might be sufficient.

[Martyn]

My common sense is tingling.

How can this possibly work on USB? USB 3.0 (the newest iteration of the technology) can support up to 900 mA on one port. A typical laptop battery will need like what- 3,000 to 4,000 mA? You're going to need to at least use a 3 way usb splitter on this. And that's only if you have USB 3.0. You're going to need a lot of USB 2.0 ports, and you're pretty much in the dark (pun not intended) with USB 1.0.

However, given the size of the cable. I want to guess that this is the netbook model. 900mA might be sufficient.

Forget about current, usb = 5vdc output, dc in 12-20vdc :D

[JosephLeo]

Forget about current, usb = 5vdc output, dc in 12-20vdc :D

Which is why you need at least a 3 way splitter, 4 for larger batteries. 5vdc * 3 = 15vdc.

[Martyn]

Which is why you need at least a 3 way splitter, 4 for larger batteries. 5vdc * 3 = 15vdc.

:o need to read more :p

[parker.casey]

Somebody once asked me for a power cable ... with two male ends. Not only did I say no, and that it doesn't exist ... I let them know I COULD make them one. And won't.

[mjbasford]

Which is why you need at least a 3 way splitter, 4 for larger batteries. 5vdc * 3 = 15vdc.

how are you going to increase amperage and voltage? Parallel will increase amperage while series will increase voltage, so therefore you would need 9 usb to get that increase on both ends, 5*3 =15vdc then .900*3 = 2.7 * 2 = 5.4 .... i think we may be over-thinking this tho...

[JosephLeo]

how are you going to increase amperage and voltage? Parallel will increase amperage while series will increase voltage, so therefore you would need 9 usb to get that increase on both ends, 5*3 =15vdc then .900*3 = 2.7 * 2 = 5.4 .... i think we may be over-thinking this tho...

Agree. however this wonderful inventor did it, we shall just call it magic.